Assuming frictionless conditions, a table has a hanging mass, m1, over a pulley

Question

Assuming frictionless conditions, a table has a hanging mass, m1, over a pulley at the left side and another hanging mass, m2, over a pulley on the right side. These two masses are connected to a third mass, m3, resting on the table surface. Light cords connect m1 to m3 and m3 to m2 so that all three move together. a) if m1 = .2kg, m2 = .5kg, & m3 = .3kg, what will be the acceleration of the system? b) If m1 = .45kg, & m2 = .3kg, & m3 = .25kg what is the new accelration of the system?

Explanation / Answer

consider to the right being positive then two forces will move the blocks m1g and m2g if right is postive m2g - m1g = (m1 + m2 + m3 )a a) a = (.5-.2)/(.2+.5+.3) *9.81=2.943 m/s^2 b) a = (.3 -.45)/(.45+.3+.25) *9.81=-1.47 m/s^2 - means the acceleration is to the left.

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