Please help! A way to go about solving it is preferred. 20) In tomatoes, the tra

Question

Please help! A way to go about solving it is preferred. 20) In tomatoes, the traits of potato leaves, yellow fruit, hairy stems, oblate fruit, and white petals are each caused by a dominant allele at a different autosomal locus. You grow 100 individuals that are hetrozygous for each locus under a range of environmental conditions (soil nitrogen concentration), the number of individuals that showed the expected phenotype is given n the table below. 3% 100 85 596 | 796 | 10% 100 100o 85 trait I nitrogen potato leaf 100 yellow fruit 85 85 95 80 100 100 hairy stem 75 80 85 9585 95 oblate fruit 95 90 white petals Which of the traits displays variable expressivity? a) all of them b) all but potato leaf c) all but potato leaf and yellow fruit d) only potato leaf and yellow fruit e) you can't tell because the alleles are dominant 21) Internode length in little bluestem is controlled by four independently assorting genes; each dominant allele contributes equally (across loci) to the phenotype (i.e., each dominant allele increases the phenotype by the same increment, each recessive allele adds nothing). If two individuals that are heterozygous at all four loci are crossed, how many different phenotypes will be observed in the offspring? a) one b) three c) six d) nine e) sixteen 22) A standard chromosome can be represented as abc defgh (where "represents the centromere), and from this, a chromosomal aberration arises that can be represented as abc degfh. This is known as a: a) deletion b) duplication c) inversion d) translocation e) transposition

Explanation / Answer

Answer

20. All but potato leaf and yellow fruit.

Variable expressivity is a phenotype is expressed to a different degree among individuals with the same genotype.

21. E 16

Consider   AA   BB Cc   Dd   X AA BB Cc Dd        2 genes are heterozygous

         Possible combination of gametes ABCD, ABcD, ABCd, ABcd  

    Cross between ABCD, ABcD, ABCd, ABcd   X ABCD, ABcD, ABCd, ABcd  

Therefor 4 X 4 = 16

22. C   Inversion

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