In the circuit in the figure, V1 is 10.35 V , V2 is 19.85 V , R1 is 16.0 , R2 is

Question

In the circuit in the figure, V1 is 10.35 V, V2 is 19.85 V, R1 is 16.0 , R2 is 35.0 , and R3 is 74.0 . Both batteries are ideal. What is the rate at which energy is dissipated in R1?

What is the rate at which energy is dissipated in R2?

What is the rate at which energy is dissipated in R3?

What power is emitted by battery 1?

What power is emitted by battery 2?

In the circuit in the figure, V1 is 10.35 V, V2 is 19.85 V, R1 is 16.0 omega, R2 is 35.0 omega, and R3 is 74.0 omega. Both batteries are ideal. What is the rate at which energy is dissipated in R1? What is the rate at which energy is dissipated in R2? What is the rate at which energy is dissipated in R3? What power is emitted by battery 1? What power is emitted by battery 2?

Explanation / Answer

51*I1+35*I2=10.35

35*I1+109*I2=19.85

to eliminate I1, multiply row one by -35 and eliminate row two I1 by 51

-35*35*I2=- 10.35*35==>109*51*I2=19.85*51

- 1225*I2= - 362.25==>5559*I2=1012.35

4334*I2=650.1==>I2=650.1/43340.15 A=I2

the same procedure to eliminate I2

51*109*I1=10.35*109==>35* - 35*I1=19.85* - 35

5559*I1=1128.15==> - 1225*I1= - 694.75

4334*I1=433.4==>I1=433.4/43340.1 A

I1=0.1 A==>I2=0.15 A==>IR2=0.1+0.15=0.25 A==>I2*R=0.252*352.1875 W

IR3=I2*R=0.152*741.665 W

Batt 1 P=I*V=0.1*10.351.035 W

Batt 2 P=I*V=0.15*19.852.9775 W

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