In the circuit in the figure, V1 is 26.75 V, V2 is 41.00 V, R1 is 19.0, R2 is 44
ID: 1281731 • Letter: I
Question
In the circuit in the figure, V1 is 26.75 V, V2 is 41.00 V, R1 is 19.0, R2 is 44.0, and R3 is 76.0. Both batteries are ideal. What is the rate at which energy is dissipated in R1?
What is the rate at which energy is dissipated in R2?
What is the rate at which energy is dissipated in R3?
What power is emitted by battery 1?
What power is emitted by battery 2?
In the circuit in the figure, V1 is 26.75 V, V2 is 41.00 V, R1 is 19.0, R2 is 44.0, and R3 is 76.0. Both batteries are ideal. What is the rate at which energy is dissipated in R1? What is the rate at which energy is dissipated in R2? What is the rate at which energy is dissipated in R3? What power is emitted by battery 1? What power is emitted by battery 2?Explanation / Answer
Let I1 be current through R1 and I2 through R3 ,so Currentr through R2 is
I3=I1+I2------------------------1
Applying KVL in left loop
-V1+I1R1+(I1+I2)*R2=0
63I1+44I2=26.75--------------------2
Applying KVL in right loop
-V2+I2R3+(I1+I2)*R2=0
44I1+120I2=41----------------2
solving 2 and 3 we get
I1=0.25 A
I2=0.25 A
I3=0.25+0.25=0.5 A
a)
Power dissipated in R1 is
P=I12R1=0.252*19 =1.1875 Watts
b)
Power dissipated in R 2 is
P2=I32R2=0.52*44=11 Watts
c)
Power dissipated in R3 is
P3=I22*R3=0.252*76=4.75 Watts
d)
Power emmited by battery 1 is
PE1=V1I1=26.75*0.25 =6.6875 Watts
e)
Power emmitted by battery 2
PE2=V2I2=41*0.25=10.25 Watts