In the circuit in the figure, V1 is 43.00 V, V2 is 47.80 V, R1 is 35.0 ?, R2 is
ID: 1905883 • Letter: I
Question
In the circuit in the figure, V1 is 43.00 V, V2 is 47.80 V, R1 is 35.0 ?, R2 is 90.0 ?, and R3 is 59.0 ?. Both batteries are ideal. What is the rate at which energy is dissipated in R1? What is the rate at which energy is dissipated in R2? What is the rate at which energy is dissipated in R3? What power is emitted by battery 1? What power is emitted by battery 2?
In the circuit in the figure, V1 is 43.00 V, V2 is 47.80 V, R1 is 35.0 ?, R2 is 90.0 ?, and R3 is 59.0 ?. Both batteries are ideal. What is the rate at which energy is dissipated in R1? What is the rate at which energy is dissipated in R2? What is the rate at which energy is dissipated in R3? What power is emitted by battery 1? What power is emitted by battery 2?Explanation / Answer
Applying KCL analysis
I1+I2+I3=0
V-V1/R1+V/R2 +V-V2/R3 =0
V(1/R1 +1/R2+1/R3) =V1/R1 +V2/R3
V(1/35 +1/90 +1/59) =43/35 +47.8/59
0.0566V =2.087
V=36V
I1 =36-43 /35 =-0.2A
I2=36/90 =0.4A
I3 =36-47.8/59 =-0.2A
energy is dissipated in R1
PR1 =I12R1 =(-0.2)2*35 =1.4W
energy is dissipated in R2
PR2 =I22R2 =0.42*90 =14.4W
energy is dissipated in R3
PR3 =I32R3 =0.22*59 =2.36W
Power emitted by battery 1
P=VI =43*0.2 =8.6W
power emitted by battery 2
P=47.8*0.2=9.56