I tried finding the area and was unsuccessful. So now I am stuck. The graph show
ID: 1967947 • Letter: I
Question
I tried finding the area and was unsuccessful. So now I am stuck.
The graph shows the component of a force acting on an object, in newtons, versus the position of the object, in centimeters. Find the work done by the force over the specified intervals of displacement: xi = 0.0cm, Xf = 5.1 cm: W = xi = 6.0 cm, x = 12.7 cm: W = xi = 14cm, xf = 17.7cm: W = When an object is displaced from one position to another along a single axis, the work done by forces acting on that object is defined by the relation W = Fx times delta x Therefore, on a graph of Fx vs x, the work done by the force over some interval of displacement is represented as the area between the curve and the x - axis, bounded by vertical lines at the end - points of the interval.Explanation / Answer
Finding the area between the the right method, so being unsuccessful is probably just the result of some unlucky mistakes. Also, remember that when the area is on both sides of the x-axis, the total work is equal to the sum of areas if the top half is positive and the bottom half is negative. This is actually the result of subtracting negative work, which I will show you when I do the calculations, though you should remember that work is a scalar quantity without any distinctions regarding distance. In addition, remember to convert to meters, and I don't know if you want the answers in significant digits or not (so I'll give an exact answer and an answer rounded to significant digits).
a) Work = (4 N) (0.003 m) + (1/2) (4 N) (0.001 m) + (8 N) (0.0051m - 0.003m)
Work = 0.0308 J 0.031 J
b) Work = ((1/2) (8 N) (0.003 m)) - ((1/2) (-6 N) (0.002m) + (-6 N) (0.0127m - 0.011m))
Work = 0.0282 J 0.028 J
c) Work = - ((1/2) (-4 N) (0.002 m) + (-2 N) (0.0177m - 0.014m))
Work = 0.0114 J 0.011 J