I tried about 3 answers and none worked, so if you can find them that would be g

Question

I tried about 3 answers and none worked, so if you can find them that would be great.

In the figure below, determine the point (other than infinity) at which the electric field is zero. (Let q1 = -2.35 muC and q2 = 6-50 muC.) The electric field of each particle is described by the following. E = ke q/r2r Let x represent the distance from the negatively charged particle q- to the zero-field point to its left. Then 1.00 m + x is the distance from the positive particle of charge q+ to this point. At this point, we want to satisfy the condition E+ + E_ = 0, so we have Taking the square root of both sides and cross-multiplying to clear fractions, gives

Explanation / Answer

Electric field will be zero close to the smaller charge i.e left of q1 since in between the field is in same direction

E=Kq1/x^2(i)+Kq2/(1+x)^2(-i)=0

or

q1/x^2(i)=q2/(1+x)^2(i)

or

(1+x)/x=sqrt(q2/q1)

or

1+x=1.663x

or

x=1.51m left of the charge q1

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