For the final section of the lab. the student is asked to investigate the energy

Question

For the final section of the lab. the student is asked to investigate the energy distribution of the spring system described above Calculate the velocity and potential energy for each displacement given and insert the correct answer using the "choices" column. Start by finding the velocity at maximum displacement. Then calculate the potential energy al this distance, this is the total energy of the system. Next, find the potential energy at 23 5 cm. and use conservation of energy to solve for the kinetic energy at 23.5 cm. Finally, use the kinetic energy to find the velocity at 23.5 cm.

Explanation / Answer

so we will need k

.295*9.81 = k*.295
k=9.81

so in part a ) PE = 1/2 kx^2 = 0.5*9.81*.295^2=0.427

in the next part b)
PE = 1/2 *9.81*.175^2=0.15

so KE = .427-.15 = 1/2 m v^2
v = sqrt( 2*(.427-.16)/.295)=1.345 m/s

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