Part A Here on Earth, a simple pendulum of length L is observed to have a freque

Question

Part A Here on Earth, a simple pendulum of length L is observed to have a frequency f. If another pendulum on Earth is observed to have a frequency that is 29f, what is its length?

29L
5.385L
1682L
L/5.385
841L
L/1682
L/29
L/841


Part B Here on Earth, a simple pendulum of length L is observed to have a frequency f. On another planet a pendulum of length L is observed to have a frequency of 18f. What is the acceleration due to gravity on this planet? In the answers below, g = 9.8 m/s2.
648g
g/648
g/4.243
324g
4.243g
g/324
g/18
18g

Explanation / Answer

L/29^2 = L/841 g*18^2 = 324g

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---