Part A Here on Earth, a simple pendulum of length L is observed to have a freque

Question

Part A Here on Earth, a simple pendulum of length L is observed to have a frequency f. If another pendulum on Earth is observed to have a frequency that is 97f, what is its length?

A. 97L
B. L/9409
C. 18818L
D. L/97
E. 9.849L
F. 9409L
G. L/18818
H. L/9.849


Part B Here on Earth, a simple pendulum of length L is observed to have a frequency f. On another planet a pendulum of length L is observed to have a frequency of 20f. What is the acceleration due to gravity on this planet? In the answers below, g = 9.8 m/s2.
A. 4.472g
B. 800g
C. 20g
D. g/20
E. 400g
F. g/400
G. g/4.472
H. g/800

Explanation / Answer

f = (1/2)(g/L)

Therefore

L' = L/9409

B. L/9409

=======================================

f = (1/2)(g/L)

E. 400g

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