Part A Here on Earth, a simple pendulum of lengthL is observed to have a frequen

Question

Part A Here on Earth, a simple pendulum of lengthL is observed to have a frequency f. If another pendulum on Earthis observed to have a frequency that is 88f, what is its length?
1 88L L/88    L/15488 L/774415488L L/9.3819.381L 7744L
Part B Here on Earth, a simple pendulum of lengthL is observed to have a frequency f. On another planet a pendulumof length L is observed to have a frequency of 41f. What is the acceleration due to gravity on thisplanet? In the answers below, g = 9.8 m/s2. 2 6.403g 1681g    g/3362 g/41g/6.403 g/16813362g 41g 1 88L L/88    L/15488 L/774415488L L/9.3819.381L 7744L 1 88L L/88    L/15488 L/774415488L L/9.3819.381L 7744L 1 2

Explanation / Answer

T = 2(L/g), 1/f = 2(L/g),1/f2 = (2)2L/g, (2)2Lf2 = g, A) Lf2 = constant Lf2 = L'(88f)2 L' = L/7744 B) (2)2Lf2 = g, g/f2 = constant g/f2 = g'/(41f)2 g' = 412g = 1681 g

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