Part A Here on Earth, a simple pendulum of lengthL is observed to have a frequen
ID: 1729011 • Letter: P
Question
Part A Here on Earth, a simple pendulum of lengthL is observed to have a frequency f. If another pendulum on Earthis observed to have a frequency that is 29f, what is its length?1 L/841 841L L/29 L/5.385L/1682 5.385L1682L 29L
Part B Here on Earth, a simple pendulum of lengthL is observed to have a frequency f. On another planet a pendulumof length L is observed to have a frequency of 58f. What is the acceleration due to gravity on thisplanet? In the answers below, g = 9.8 m/s2. 2 g/7.616 6728g 3364g g/336458g g/58g/6728 7.616g 1 L/841 841L L/29 L/5.385L/1682 5.385L1682L 29L 1 L/841 841L L/29 L/5.385L/1682 5.385L1682L 29L 1 2
Explanation / Answer
T = 1/f = 2(L/g) A) for fixed g, if f increases by a factor 29, T decreases by afactor 29, L decreases by 29^2=841 answer = L/841 B) for fixed L, if f increases by a factor 58, T decreases by afactor 58, g increases by 58^2=3364 answer = 3364g