Please answer both parts for a full rating PART A: A car, mass m 1 is moving to
ID: 2035003 • Letter: P
Question
Please answer both parts for a full rating
PART A:
A car, mass m1 is moving to the right on a frictionless air track. It collides with a second car, mass m2, which is initially at rest. Which of the following statements are true? (If A and E are true, and the others are not, enter TFFFT).
A) If car 1 sticks to car 2, the car1-car2 system must move to the right after the collision.
B) If the collision is elastic, car 1 must always come to a stop after the collision.
C) If car 1 is much lighter than m2, and the collision is perfectly elastic, car 1 will continue heading to the right with nearly its original speed after the collision.
D) Suppose (for this statement only) that car 2 was NOT initially at rest, but was instead heading towards car 1 with equal (but opposite) momentum before the collision. After the collision, the cars must both be at rest.
E) If car 1 sticks to car 2, the final total kinetic energy of the car1-car2 system is equal to the initial total kinetic energy of the two cars.
PART B:
FORD J DDDDD ZW TWExplanation / Answer
A : T , The net momentum is to the right and hence both move to the right
B: F, this can heppen only if both are same mass ( m1= m2) , it is not the case
C: F, if m1 is much lighter then momentum of m2 after collision is negligible and m1 bounces back to left to conserve momentum.
D: F, with this situation momentum is not conserved.
E: F, with inelastic collision energy si not conserved, only momentum is conserved.
PartB
A : L , greater mass less vel , since momentum mv is same
B: L , v2 = 2gh , v is less , h is less
C: E, once one of the blocks loose contact with the spring, no more force is exerted by the spring.
D: L, KE = p2/2m , p is same for both M1 is larger hence KE is less
E : E, the sprign exertes equal force at both eneds and hence on both the blocks.
F: E , total momentum is conserved, it is before and hence must be equal in magnitude for both just after release.