Constants I Poriodic Table How far from child A is their CM7 2 kids take part in

Question

Constants I Poriodic Table How far from child A is their CM7 2 kids take part in a tug of war on an icy playground (don't try this at home). There is zero friction between their shoes and the ground., Child A has a mass of 35-kg and child B hasa mass of 50-kg. They are inidally standing 11 m apart Express your answer using two significant figures -Part B s the end of a rope and child B pulls on the rope so that he moves toward chid A. How far will child B have moved when he collides with child A Express your answer using two significant figures SuomitResauses A

Explanation / Answer

a) The distance between the center of mass to the children is in the inverse proportion of the masses of the children.

Distance of A from the CM is = 11 x 50/(50+35) = 6.47 m

b) Since the surface is frictionless, the force used by B will act equally upon both A and B in accordance with Newton's third law. Therefore,

maaa = mbab

35 x aa = 50 x ab

ab/aa = 35/50 = 0.7

Since both bodies are at rest u=0.

S=0.5 at2. Time taken by both bodies are same as they collide each other at the same instant. So the ratio S/a will be same for both the bodies.

sa/aa = sb/ab

sb = sa xab /aa = sa x 0.7

But, sb + sa = 11. Therefore, sa = 11 - sb

sb = (11 - sb) x 0.7 = 7.7 - 0.7sb

sb = 7.7/1.7 = 4.52m

B has travelled 4.52m

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