Part A: A ray of light travels through vacuum (n=1.00) and is incident upon a fl

Question

Part A: A ray of light travels through vacuum (n=1.00) and is incident upon a flat sheet of glass (n=1.50) at 40 degrees from the normal. Some of the light is reflected from the glass, and some of the light is refracted, traveling through the glass. What is the angle of reflection?

Part B: A ray of light travels through vacuum (n=1.00) and is incident upon a flat sheet of glass (n=1.50) at 40 degrees from the normal. Some of the light is reflected from the glass, and some of the light is refracted, traveling through the glass. What is the angle of refraction?

Explanation / Answer

Part A

According to law of reflection

Angle of incidence = angle of reflection

given that Angle of incidence = 40 deg

So Angle of reflection = 40 deg

Part B

Using snell's law:

n1*sin A1 = n2*sin A2

sin A2 = (n1/n2)*sin A1

A2 = angle of refraction = ?

A1 = angle of incidence = 40 deg

n1 = refractive index of vacuum = 1.00

n2 = refractive index of glass = 1.50

So,

A2 = arcsin ((1/1.50)*sin 40 deg)

A2 = 25.37 deg

Please Upvote.

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