Course Contents.. \" Assignment 10 Submerging in Water TimerNotes Evaluat Feedba

Question

Course Contents.. " Assignment 10 Submerging in Water TimerNotes Evaluat FeedbackPrint Info Submerging in Water Due on Tuesday, May 1 at 03:00 pm (EDT) You can determine the index of refraction of a substance by determining its critical angle. What is the index of refraction of a substance that has a critical angle of 53.4° when submerged in water? What is the substance, based on Table 25.1? The substance is most likely Submit Answer Tries 0/10 What would the critical angle be for this substance in air? Submit Answer Tries o/10

Explanation / Answer

Given,

theta-c = 53.4 deg

we know that

n1 sin(theta-c) = n2 sin90

n1 = n2/sin(theta-c)

n1 = ? ; n2 = 1.33 (water) ;

n1 = 1.33/sin53.4 = 1.66

Hence, n2 = 1.66

The substance is most likely FLINT GLASS

again using the same relation

theta-c = sin^-1(n2/n1)

n2 = 1 (air) ; n1 = 1.66 ;

theta-c = sin^-1(1/1.66) = 37.04 deg

Hence, theta-c = 37.04 deg

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