Constants Periodic Table Part A You\'re an electrical engineer designing an alte

Question

Constants Periodic Table Part A You're an electrical engineer designing an alternator (the generator that charges a car's battery). Mechanical engineers specify a 10-cm-diameter rotating coil, and you determine that you can fit 250 turns in this coil. To charge a 12-V battery, you need a peak output of 20 V when the alternator is rotating at 1600 rpm. What do you specify for the alternator's magnetic field?HINT: Notice that the rotation rate of the coil is given in revs per minutes, not revs per second. Express your answer to two significant figures and include the appropriate units. Bal Units Submit Request Answer

Explanation / Answer

Area of coil

A=pi*D2/4 =pi*0.12/4 =7.854*10-3 m2

angular frequency

W=1600*(2pi/60) =167.55 rad/s

Peak induced Voltage

VP=NBAW

=>20 =250*(7.854*10-3)*B*167.55

B=0.0608 T or 60.8 mT

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