Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Class t I Help ssignment-5 Begin Date: 4/11/2018 12:01:00 AM-Due Date:4/18/2018

ID: 2039829 • Letter: C

Question

Class t I Help ssignment-5 Begin Date: 4/11/2018 12:01:00 AM-Due Date:4/18/2018 11:59.00 PM End Date: 4/19/2018 11:59:00 PM (16%) Problem 3: You can determine the index of refraction of a substance by measuring its critical angle for total internal reflection. Randomized Variables 50% Part (a) What is the index of refraction of a substance that has a critical angle of 64A" when submerged in water (with index of refraction 1.333)? Grade Summary Deductions 6% Potential 94% sin0 cosO tanO7 8 9 cotanO asin acos0 atan0 acotan sinh0 coshO tan cotanhO Attempts remaining % per attempt) view 3% 3% 0 O Degrees Radians vo Submit Hint Hints: 1% deduction per hint. Hints rernaining: 2 Feedback: 0 deduction per feedback 50% Part (b) what would the critical angle be for this substance in air?

Explanation / Answer

part a:

let index of refraction be n.

incident angle=64.8 degrees

refraction angle=90 degrees

index of refraction of water=1.333

using snell’s law:

n*sin(64.8)=1.333*sin(90)

==>n=1.4732

part b:

let critical angle when the substance is in air be theta

using snell’s law:

1.4732*sin(theta)=1*sin(90)

==>theta=42.75 degrees