Remember the basic formulas: p + q = 1 (relative frequency/proportion of two dif
ID: 206928 • Letter: R
Question
Remember the basic formulas: p + q = 1 (relative frequency/proportion of two different alleles in a population) p2 2pq+q2 -1 (relative frequency/proportion of given genotypes in a population) frequency of the dominant allele in the population q = frequency of the recessive allele in the population p2-percentage of homozygous dominant individuals q2 = percentage of homozygous recessive individuals 2pq percentage of heterozygous individuals 1. You have sampled a population of 10,599 individuals that you know is in Hardy- Weinberg equilibrium (HWE). The percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate the following: a. The frequency of the "aa" genotype. b. The frequency of the "a" allele. c. The frequency of the "A" allele. d. The frequencies of the genotypes "AA" and "Aa." e. The frequencies of the two possible phenotypes if "A" is completely dominant over "a. f) How many of the individuals in this population show the dominant phenotype?Explanation / Answer
Ans1.
a) frequency of aa genotype=36%, i.e. 0.36.
b) frequency of allele a =?
aa=0.36
a=0.36
a=0.6
Thus, frequency of allele a is 0.6.
c) frequency of A allele?
A+a=1
A+0.6=1
A=0.4
(d) frequency of AA=0.4×0.4=0.16
Frequency of Aa=2×0.4×0.6=0.48
(e) frequency of dominant Phenotype=AA+Aa
=0.16+0.48
=0.64
Frequency of recessive phenotype (aa)
=0.36
(F) dominant Phenotype is shown by 0.64 or 64%
=0.64×total population
=0.64×10599
=6783.36
=6783 individuals