Consider an electron (m - 9.11 times 10^-31 kg and q- -1.6 times 10^-19 C) trave

Question

Consider an electron (m - 9.11 times 10^-31 kg and q- -1.6 times 10^-19 C) traveling to the right at a constant speed of 3 times 10^4 m/s and entering into a uniform, 0.35T magnetic field which points out of the page as shown in the figure. When the electron enters the field, its path will have radius equal to ___ m and it will travel in the (clockwise/counterclockwise) direction. Round your answer to the nearest integer and enter it in exponential notation (ex//2E-3). Choose and copy the "clockwise" or "counterclockwise" exactly for answer two.

Explanation / Answer

(a) When it enters a magnetic field, it experiences a force called magnetic lorentz force given by ,

Fmag.= q(v x B) involves a vector product between velocity vector v of moving charge and magetic field B

By considering the direction of B and v, it can be understood that electron will undergo a circular path

To find the radius, we equate Centripetal force = Lorentz force

i.e. m v2 / r = qvB

so radius of circular path, r = mv / qB = 9.1*10-31 *3*104 / 1.6*10-19 *0.35

r = 48.75*10-8 m

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