Analyze the program in Figure 2. The program controls three lights: L1, L2, and
ID: 2081894 • Letter: A
Question
Analyze the program in Figure 2. The program controls three lights: L1, L2, and L3.
Assume SW closes and T4:1 is enabled. Which of the lights, if any, are on while T4:1 is timing?
Again, assume SW is closed. When T4:1 is done timing it enables T4:2 to start timing. Which light(s) are on while T4:2 is timing?
All the lights are off when T4:3/DN = 1. Again, assuming SW is closed, how long from the time T4:3/DN = 1 until T4:3 resets?
As long as SW is closed, will the timing cycle repeat?
000 001 002 003 004 005 006 /0 E SW T4:1 /DN T4 2/DN T4 3/DN T4 1/El T4 T4:3/EN T4:4/DN T4:3/DN T4:3/DN T4:3/DN /0 SW I: 1/0 /0 SW TON Timer On Delay EN T4.1 Timer Time Base 0.1 CDN Preset Accum. TON Timer On Delay H EN T4:2 Timer Time Base 0.1 Preset Accum. TON Timer On Delay H EN T4:3 Timer Time Base 0.1 Preset Accum. TON Timer On Delay EN T4:4 Timer Time Base 0.1 CDN Preset Accum. O 210 L1 O:2/1 O: 2/2Explanation / Answer
1. Assuming that the SW I:1/0 is closed and T4:1 is timing, the rung 004 will be activated thereby only O:2/0 and thus light L1 will be activated.
2. Similarly When T4:2 is timing, the rung 005:will be activated thus light L2 will be On.
3. If the switch is closed again once the T4:3/DN = 1, the timer T4:4 and T4:1 will be timing simultaneously and thus after 1s for T4:1 and 1s for T4:2, T4:3 will be timing again, this after 2s it will be reset.
4. If the switch is continuously closed, it will not repeat the cycle because, once the T4:4/DN is set to 1 the cycle will stop.
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