Initially, for the circuit shown, the switch S is open and the capacitor voltage
ID: 2095908 • Letter: I
Question
Initially, for the circuit shown, the switch S is open and the capacitor voltage is 72 V. The resistance and capacitance are 2.3 M Ohm and 18 mu F respectively. The switch S is closed at time t = 0. In Figure, the charge in mu C on the capacitor when the current in the circuit is 10 mu A, is: What would be the DMM reading (with one decimal place) of voltage in volts on AC for the signal shown in the figure? Use the figure below which plots the voltage drop across a capacitor as a function of time as the capacitor is being charged to estimate the time constant in milliseconds for the RC circuit. Express the answer with one decimal place.Explanation / Answer
The voltage reaches steady state at 0.0025 s The time taken to reach steady state is 5 time constants
So 1 time constant is 0.0005 seconds i.e. 0.5 ms or 500 micro seconds
In anycase as the figure is not accurate steady state may be even at 0.003 seconds
Inthat case time constant is 0.0006 seconds or 0.6 ms or 600 micro seconds