Consider the combination of capacitors in the figure below. (Let C 1 = 20.0 Cons

Question

Consider the combination of capacitors in the figure below. (Let C1 = 20.0

Consider the combination of capacitors in the figure below. (Let C1 = 20.0 mu F and C2 = 1.00 mu F.) Find the equivalent single capacitance of the two capacitors in series and redraw the diagram (called diagram 1) with this equivalent capacitance In diagram 1 find the equivalent capacitance of the three capacitors in parallel and redraw the diagram as a single battery and single capacitor in a loop. Compute the charge on the single equivalent capacitor Returning to diagram 1, compute the charge on each individual capacitor.

Explanation / Answer

A. C' = C1 x 8 / (C1 +8) = 5.71 uF

B) Cnet = 4 + C2 + 5.71 =10.71 uF

c) Q = Cnet x V = 3.857 x 10-4 C

d) Q on 4 = 4 x 10-6 x 36 = 1.44 x 10-4 C

Q on C2 = 0.36 x 10-4 C

e) Q = 8uFV1 = 20uF(36 - V1)

V1 = 25.71 V

so Qon 20 uF = on 8uF = 25.71 x 8 x 10-6 = 2.057 x 10-4 C

F ) V on 20uF = 36 - 25.71 = 10.29 V

G) v = 36 volt

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