Could anyone please provide a full working solution to this question cannot find

Question

Could anyone please provide a full working solution to this question cannot find in solutions. Thanks

The work function for platinum is 6.35 eV. Ultraviolet light of wavelength 150 nm is incident on the clean surface of a platinum sample. We wish to predict the stopping voltage we will need for electrons ejected from the surface. (a) What is the photon energy of the ultraviolet light? (b) How do you know that these photons will eject electrons from platinum? (c) What is the maximum kinetic energy of the ejected photoelectrons? (d) What stopping voltage would be required to arrest the current of photoelectrons?

Explanation / Answer

h =planck's constant , c = speed of light

a) photon energy = (hc/wavelength) = 8.2825eV

b) as photon energy> work function, therefore electron can be ejected

c) maximum kinetic energy of electron = (hc/wavelength) - work function = 1.9325eV

d) stopping voltage = maximum kinetic energy/e = 1.9325V

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