Consider the combination of resistors shown in the figure below. 12 ? A 6 ? A 5

Question

Consider the combination of resistors shown in the figure below.

                12 ?                                        A                              6 ?                                        A                              5 ?                                        A                              4 ?                                        A                              8 ?                                        A              Consider the combination of resistors shown in the figure below. Find the equivalent resistance between point a and b. If a voltage of 41.3 V is applied between points a and b, find the current in each resistor.

Explanation / Answer

equivalent resistance = 12||6 + 5 + 4||8 = 12*6/(12+6) + 5 +4*8/(4+8) = 11.67 ohm

b)

net current = net voltage/net resistance = 41.3/(11.67) = 3.54 A

now current will divide in the 12 and 6 ohm as per their resistance ratio.

So, let current in 6 ohm = x

so, current in 12 ohm = x/2 <----as resistance is twice so current is half

So, total current in 12 + 6 ohm = x+x/2 = 3.54

So, x = 2.36 A

So, current in 12 ohm = 2.36/2 = 1.18 A <-----answer

current in 6 ohm = 2.36 A <-------answer

current in 5 ohm = 3.54 A <----answer

Similary , current in 4 ohm = 2.36 A <----answer

current in 8ohm = 1.18 A <-----answer

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