In the figure below, block A (mass 1.6 kg) slides into block B (mass 1.9 kg), al

Question

In the figure below, block A (mass 1.6 kg) slides into block B (mass 1.9 kg), along a frictionless surface. The directions of the three velocities are indicated; the corresponding speeds are vAi = 5.5 m/s, vBi = 2.5 m/s, and vBf = 4.9 m/s.

(a) What is the speed of velocity vAf? (m2 = 1.9 kg.)
     m/s

Please show all work and equations. I need all the help I can get.

In the figure below, block A (mass 1.6 kg) slides into block B (mass 1.9 kg), along a frictionless surface. The directions of the three velocities are indicated; the corresponding speeds are vAi = 5.5 m/s, vBi = 2.5 m/s, and vBf = 4.9 m/s. What is the speed of velocity vAf? (m2 = 1.9 kg.) m/s

Explanation / Answer

As no external force is acting on the system of the block A and B.

thus, momentum of the system is conserved.

=>initial mometum=final momentum of the system

=>Ma*Vai+Mb*Vbi=Ma*Vaf+Mb*Vbf

=>1.6*5.5+1.9*2.5=1.6*Vaf+1.9*4.9

=>Vaf=2.65 m/s

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