In the figure are shown three capacitors with capacitances c1 = 6.16?10?6 F, c2
ID: 2147290 • Letter: I
Question
In the figure are shown three capacitors with capacitances c1 = 6.16?10?6 F, c2 = 2.91?10?6 F, and c3 = 4.96?10?6 F. The capacitor network is connected to an applied potential V_ab. After the charges on the capacitors have reached their final values, the charge on the second capacitor is 4.02?10?5 C.
A. What is the charge Q_1 on capacitor C_1? (C)
B. What is the charge on capacitor C_3? (C) Express your answer in microcoulombs to three significant figures.
C. What is the applied voltage, V_ab? (V)
Explanation / Answer
let the charge on c2 be q2 ,c1 be q1 and c3 be q3 therefore Vad will be q2 x c2 Vad= q2 x c2 A > Hence q1 can be found by Vad/c1 q1=Vad/c1 B > total charge q1 + q2 on capacitors 1 and 2 will be Vad/(c1+c2 ) therefore the charge on C3 will be q1+q2 q3=Vad/(c1+c2) C > Vab = Vad + Vdb = Vad + q3/c3 All the equations have been written I can't read the ( powers of ten )values of c1 ,c2, c3 U can just substitue those values and get the the answers for A,B and C