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In the figure are shown two converging lenses with x 2 = 1 m. The lens on the le

ID: 1377461 • Letter: I

Question

In the figure are shown two converging lenses with x2 = 1 m. The lens on the left (Lens 1) has a focal length of 0.25 m while the one on the right (Lens 2) has a focal length of 0.2 m. An object 2.4 cm high is located x1 = 0.424 m to the left of Lens 1.

1)

Consider the image of the object formed by Lens 1. Give its distance as measured from Lens 1 and the image height.

Distance =

m  

2)

Height =

cm  

3)

Now consider the image formed by Lens 1 as the object for Lens 2. Locate the image formed by Lens 2 as measured from Lens 2 and give the height of the image.

Distance =

m  

4)

Height =

cm  

Explanation / Answer

1)
given f1 = 0.25 m

u1 = 0.424 (object distnace for first lense)

1/u1 + 1/v1 = 1/f1

1/v1 = 1/f1 - 1/u1

1/v1 = 1/0.25 - 1/0.424

v1 = 0.609 m (image distance of first lense)

2)

magnification, m1 = -v1/u1

= -0.609/0.424

= 1.44

image height = m1*object height

= 1.44*2.4

= 3.45 cm

3)

object distnce for second lense, u2 = 1 - 0.609 = 0.391 m

given f2 = 0.2 m

1/u2 + 1/v2 = 1/f2

1/v2 = 1/f2 - 1/u2

1/v2 = 1/0.2 - 1/0.391

v1 = 0.409 m (image distance of second lense)

4)

magnification, m2 = -v2/u2

= -0.409/0.391

= 1.046

image height = m2*object height

= 1.046*3.45

= 3.6 cm