See the figure (http://s19.postimage.org/3yjss8twj/CC207b.png). With the switch
ID: 2154594 • Letter: S
Question
See the figure (http://s19.postimage.org/3yjss8twj/CC207b.png). With the switch in position A, the capacitor becomes charged. After a long time, the capacitor charge approaches q = C ?.Now, suppose the capacitor is fully charged, when, at time t = 0, the switch is moved from A to B.
B,C,D have 2 numerical answers.
(A) Determine the charge q(t) and current i(t) for t > 0.
(B) Determine the energy of the capacitor U(t) as a function of time t. The initial energy, at t = 0, is U0. Calculate the energy at t = RC and at t = 0.71 RC. Express the answers as fractions of the initial energy. (No units because the answers are a ratio of energy/energy.)
(C) Determine the power P(t) dissipated in the resistor. Calculate the power at t = RC and t = 0.71 RC. Express the answers as fractions of U0/?.
(D) Determine the integrated power (the integral of P(t') from t' = 0 to t). Calculate the integrated power for t = RC and t = 0.71 RC. Express the answers as fractions of U0.
Explanation / Answer
hope this helps.. https://docs.google.com/viewer?a=v&q=cache:R_n95GK_fM4J:rfic.eecs.berkeley.edu/ee100/pdf/lect13_ann.pdf+&hl=en&gl=in&pid=bl&srcid=ADGEESjrUjrFgjcEJ5Q46To7JELvPYncqfv8VreBx1k3hqlv8k96lYSFc9EpwNYgaEfyk0tko5AMkPvI5ugFZYeVybfxECcYsc-6vnA51oOqTvnnreYmeF7B0aDbMJ0w_tedBCX-aZHy&sig=AHIEtbTPkwNQL5uuxVQ0D8YCKZd_o2QdbA