See the figure (http://s19.postimage.org/3yjss8twj/CC207b.png). Close the switch

Question

See the figure (http://s19.postimage.org/3yjss8twj/CC207b.png). Close the switch at t = 0. Determine the current delivered by the battery, i(t), as a function of time. After a long time, the charge on the capacitor will be q(?) = C?/2, and the current from the battery will be i(?) = ?/2R.


(A) Calculate the current i just after the switch is closed, as a fraction of i(?). (No units because the answer is the ratio i/i(?).)


(B) Calculate the current i when t = 0.5 RC, as a fraction of i(?).


(C) Calculate the current i when t = RC, as a fraction of i(?).

Explanation / Answer

hope this helps. https://docs.google.com/viewer?a=v&q=cache:R_n95GK_fM4J:rfic.eecs.berkeley.edu/ee100/pdf/lect13_ann.pdf+&hl=en&gl=in&pid=bl&srcid=ADGEESjrUjrFgjcEJ5Q46To7JELvPYncqfv8VreBx1k3hqlv8k96lYSFc9EpwNYgaEfyk0tko5AMkPvI5ugFZYeVybfxECcYsc-6vnA51oOqTvnnreYmeF7B0aDbMJ0w_tedBCX-aZHy&sig=AHIEtbTPkwNQL5uuxVQ0D8YCKZd_o2QdbA

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