Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Consider the circuit shown. Now use the frequency f = 35 Hz. (i) What are the re

ID: 2197720 • Letter: C

Question

Consider the circuit shown. Now use the frequency f = 35 Hz. (i) What are the reactances XL and XC? 5 (ii) Use the phasor drawing, and note that the resistor R1 is in series with the inductor, so calculate the impedance of this part of the circuit. Also calculate the phase angle between the current and voltage. (iii) Do the same for the other part of the circuit, where R2 is in series with the capacitor. (iv) Now, we notice that these two parts of the circuit are connected in parallel with each other. Align the phasor voltages of these two parts, and add the current phasor vectors. The magnitude of this current vector is the current drawn from the generator.Red graph is part ii and iii, blue graph it part iv.

An electric circuit connected to a wall socket (RMS voltage 120 V) is connected to an inductor L = 205 mH and a capacitor C = 336

Explanation / Answer

we know that XC = 1 / (2*?*f*C) XL = 2*?*f*L The units are ohms and they are positive real numbers. How to Calculate Impedance Impedance is the opposition of a circuit to alternating current. It's measured in ohms. To calculate impedance, you must know the value of all resistors and the impedance of all inductors and capacitors, which offer varying amounts of opposition to the current depending on how the current is changing. You can calculate impedance using a simple mathematical formula. Calculate the total resistance the circuit. The values of the resistors can be determined in 1 of 3 ways. Measure the resistance of each resistor with an ohmmeter or a multimeter. Remove the resistor from the circuit, place the probes on each side and read the display, which will give the resistance in ohms. Study the circuit diagram, which will have each resistor labeled with its value in ohms. Resistors are indicated by the letter R. Read the color coding on the resistor, which will provides information on its value and tolerance. You can find a resistor color code guide online. When calculating total resistance, remember that resistors connected in series are added together, but resistors connected in parallel are not. Instead, for each resistor in parallel, divide 1 by the value of the resistor, then add the results for each together to get the total resistance of all the resistors in parallel. Add together the impedance of the inductors in the circuit . The result will be inductive reactance. Measuring an inductor requires removing it from the circuit and placing it in special circuit that includes a resistor and an AC power source. Instead, study the circuit diagram. Inductors are indicated by the letter L, and their values are measured in henries. Calculate the impedance of each inductor by multiplying the following: inductance in henries, frequency in hertz, the value of pi, and 2. Add together the reactance of the capacitors in the circuit . The result will be capacitive reactance. Like an inductor, measuring a capacitor requires placing it in a specialized circuit, so it's best to study the circuit diagram. Capacitors are indicated by the letter C and are measured in farads. Calculate the impedance of each capacitor in 2 steps. First, multiply the following: capacitance in farads, frequency in hertz, the value of pi and 2. Next, divide 1 by this result. Find the total reactance of the circuit . Add the sum of the impedance of all the inductors and the impedance of all the capacitors to get the total. Find the total impedance of the circuit. Square total reactance and total resistance, add the results together and take the square root of the sum. Tips Inductors oppose changes in current. They do this because as the input current increases, it induces a magnetic field that cuts across the coils. This induces a current in the coils that serves to oppose the input. As the input current drops, the magnetic field collapses and the inductor allows current to flow through the coils more easily.