A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is

Question

A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 7.0 m. The wave pulse has an amplitude of A = 0.24 m and takes t = 0.484 s to travel down the stretched length of the slinky. The frequency of the wave pulse is f = 0.49 Hz. 1) What is the speed of the wave pulse? m/s 2) What is the tension in the slinky? N 3) What is the average speed of a piece of the slinky as a complete wave pulse passes? m/s 4) What is the wavelength of the wave pulse? m 5) Now the slinky is stretched to twice its length (but the total mass does not change). What is the new tension in the slinky? (assume the slinky acts as a spring that obeys Hooke

Explanation / Answer

The average transverse or longitudinal wave velocity over a complete cycle is zero.

Starting from the equilibrium point .. the first 1/2 cycle average velocity is zero ..

being two 1/4 cycle journeys in opposite directions (to travel back to the equilibrium position for the first time).
The magnitude of the velocity is the same (v) over each 1/4 cycle .. but in opposite directions each successive 1/4 .. +v + -v = 0 for each

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