Physics Help After a ball rolls off the edge of a horizontal table at time t = 0
ID: 2221525 • Letter: P
Question
Physics Help
After a ball rolls off the edge of a horizontal table at time t = 0, its velocity as a function of time is given by V rightarrow = 1.4 I - 9.8t j. where v rightarrow is in meters per second and t is in seconds. The ball's displacement away from the edge of the table, during the time interval of 0.385 s for which the ball is in flight, is given j by To perform the integral, you can use the calculus theorem You can think of the units and unit vectors as constants, represented by A and B. Perform the integration to calculate the displacement of the ball from the edge of the table at 0 385 s.Explanation / Answer
displacement = integral (1.4 i - 9.8t j ) dt = 1.4t i - 4.9t^2j from (0 to 0.385 s) = 1.4 x 0.385 i - 4.9 x 0.385^2 j = 0.539 i - 0.726 j magnitude = sqrt (0.539^2 + 0.726^2) = 0.90445 m ans is 0.90445 m