I just need the last blank, five stars for correct answer. Thank you. Use the wo

Question

I just need the last blank, five stars for correct answer. Thank you.

Use the worked example above to help you solve this problem. A skier starts from rest at the top of a frictionless incline of height 20.0 m, as shown in the figure. At the bottom of the incline, the skier encounters a horizontal surface where the coefficient of kinetic friction between skis and snow is 0.23. Neglect air resistance. Find the skier's speed at the bottom. How far does the skier travel on the horizontal surface before coming to rest? Use the values from PRACTICE IT to help you work this exercise. Find the horizontal distance the skier travels before coming to rest if the incline also has a coefficient of kinetic friction equal to 0.23. Assume that Q = 20.0 degree. Compute the distance traveled when there is no friction on the incline. When there is friction on the incline, do you expect the distance traveled to be larger or smaller than this? m

Explanation / Answer

(a) At the bottom of the incline KE = PE. In other words:
(1/2)mv^2 = mgh ==> v = ?(2gh).

Thus, the speed of the skier on the bottom is:
v = ?(2gh)
= ?[2(9.8 m/s^2)(20.0 m)]
= 19.8 m/s.

(b) Taking friction into account, the speed of the skier at the bottom of the incline is:
KE = PE - W(friction)
= PE - F(friction)d
= PE - u(k)mgd*cos?.

Since the angle makes an angle of 20.0

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---