Please explain in detail with the steps. A 2.00kg block slides with a speed of 0
ID: 2236558 • Letter: P
Question
Please explain in detail with the steps. A 2.00kg block slides with a speed of 0.960m/s on a frictionless horizontal surface until it encounters a spring with a force constant of 1070N/m. The block comes to rest after compressing the spring 4.15cm. Part A Find the spring potential energy,U, the kinetic energy of the block,K, and the total mechanical energy of the system,E, for compressions of 0cm. (Answer in J) Part B Find the spring potential energy,U, the kinetic energy of the block,K, and the total mechanical energy of the system,E, for compressions of 1.00cm. (Answer in J) Part C Find the spring potential energy,U, the kinetic energy of the block,K, and the total mechanical energy of the system,E, for compressions of 2.00cm. (Answer in J) Part D Find the spring potential energy,U, the kinetic energy of the block,K, and the total mechanical energy of the system,E, for compressions of 3.00cm. (Answer in J) Part E Find the spring potential energy,U, the kinetic energy of the block,K, and the total mechanical energy of the system,E, for compressions of 4.00cm. (Answer in J)Explanation / Answer
A) potential energy =kx^2/2;
=1070*(.0415)^2/2;
=.921 N m
when block come in rest then kinetic energy will be =0
total energy=.921 Nm