Question
PLEASE SOLVE THE FOLLOWING
A force of 40.0 N is applied to a crate to displace it by 50 0 m. How much work is done on the crate by this force? 2.25 times 10 3 J 1.25 times 10 3 J 1.50 times 10 3 J 2.00 times 10 3 J Particle one of mass m initially moves to the right at v. Particle two of mass 2m is initially at rest After they undergo an elastic collision, particle one moves directly down What is the final speed of particle two? 0 500 v 0.250 v 0.707 v 0.577 v 0.764 v The sum of the forces acting on an object is equal to the object's momentum. the impulse the object receives. the rate of change of the object's momentum. None are correct.
Explanation / Answer
1) 2*10^3 J
2) 0.707 V
3) the rate of change of momentum