A current-carrying circular loop of radius R is placed next to a long straight w

Question

A current-carrying circular loop of radius R is placed next to a long straight wire, as shown in the diagram below. The current in the straight wire points to the right and is of magnitude 5 A.

In order to produce a net magnetic field of zero in the center of the circular loop, the current in the loop itself must be:

size: A

A current-carrying circular loop of radius R is placed next to a long straight wire, as shown in the diagram below. The current in the straight wire points to the right and is of magnitude 5 A. In order to produce a net magnetic field of zero in the center of the circular loop, the current in the loop itself mu st be:

Explanation / Answer

Bwire=?I/2?R , Bloop=?I/2R

For the net B to be zero, Bwire must equal Bloop.

I got this part correct,

the answer to part a) is .63662A

If the current in the straight wire is to the right, then the B field above it is out of the page. This means that the circle must have a B field into the page of equal magnitude to cancel out the B field of the straight wire. This means that the loop should have a clockwise current.

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