Part B: What was the initial direction (as measured counterclockwise from the x-

Question

Part B: What was the initial direction (as measured counterclockwise from the x-axis)?

Car Collision in 2D Part A: A 900- kg car collides with a 1400- kg car that was initially at rest at the origin of an x-y coordinate system. After the collision, the lighter car moves at 10.0 km/h in a direction of 30 o with respect to the positive x axis. The heavier car moves at 13 km/h at -46 o with respect to the positive x axis. What was the initial speed of the lighter car (in km/h)? Part B: What was the initial direction (as measured counterclockwise from the x-axis)?

Explanation / Answer

balancing momentum along x-axis.

900.Vx + 1400 x 0 = 900 x 10cos30 + 1400 x 13 x cos46

Vx = 22.71 km/h

balancing momentum in along y-axis

900Vy + 1400 x0 = 900 x 10sin30 - (1400 x 13 x sin46)

vy = - 9.55 km/h

speed = sqrt ( vx^2 + vy^2) = 24.63 km/h

b) angle = tan-1 (9.55 / 22.71) = 22.81 degrees below +X-axis

so 360 - 22.71 = 337.19 degrees counterclockwise

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