Please help!!! A Bald Eagle lands on a branch which then oscillates up and down.
ID: 2272310 • Letter: P
Question
Please help!!!
A Bald Eagle lands on a branch which then oscillates up and down. The female eagle is 1 meter tall and has a mass of 6kg. From a video of the landing, a biologist makes the following graph of the position of a spot on the branch From this data, determine The equilibrium displacement for the branch with the eagle on it. The effective k for the branch by applying Hookes law to the motion The period of the motion. The angular frequency, w The damping factor, a, in A=A0e at. During the spring thaw, a field ecologist needs to measure the velocity of a stream. She notices a spot where an icicle is melting and dripping water into the stream at 1 drop per second. As the drops hit the water, they send out a circular wave crest. She takes several photos of the ripples and uses the measurements to determine the stream velocity while staying warm and dry. The diagram below is made from one of the photos. Indicate with an arrow which direction the water is moving Determine the wavelength received upstream and downstream of the drip Determine the speed of the waves and how fast the water is moving Determine the wavelength of the emitted wave generated with a frequency of 1Hz by the drips The naturalist comes to a cave and wants to determine how far it extends. She pulls out a speaker and variable frequency source and determines that the cave has resonances at 25.73Hz, 42.875Hz, 60.03Hz and higher frequencies. The speed of sound is 343 m/s for the local conditions. Determine the wavelengths for the three frequencies. From the pattern, determine if the cave is open or closed at the other end. What is the depth of the cave (length)Calculate the fundamental resonant frequency and determine the mode numbers for the measured frequencies (1,2,3, etc.)Explanation / Answer
A) 1) equilibrium displacement = 0.8 m
2) K *0.8 = mg
k = 73.5 N/m
3) T = 2*pi* sqrt(m/k) = 1.79 s
4) w = angular frequency = sqrt(k/m) =3.5 rad/s
B) 1) towards right
2) lemda =1 m
3) speed = lemda/T
C) lemda1 = 343/25.73 = 13.33 m
lemda2 = 343/42.87 = 8 m
lemda3 = 343/60 = 5.7 m
2)