I\'m sorry this one\'s a bit lengthy! That\'s why so many points are being offer

Question

I'm sorry this one's a bit lengthy! That's why so many points are being offered, though only for correct answers for all four sections. Thank you so much for any and all help!

Background Information:

Electron's kinetic energy just before a collision is 2.5 x 10^-18 J

Part A

The average distance an electron travels between collisions is 2.0 micrometers. What acceleration must an electron have to gain 2.5 x 10^-18 J of kinetic energy in this distance?

Part B

What force must act on an electron to give it the acceleration found in Part A?

Part C

What strength electric field will exert this much force on an electron? This is the breakdown field strength. (Note: The measured breakdown field strength is a little less than your calculated value because our model of the process is a bit too simple. Even so, your calculated value is close.)

Part D

Suppose a free electron in air is 1.3 cm away from a point charge. What minimum charge must this point charge have to cause a breakdown of the air and create a spark?

Electron's kinetic energy just before a collision is 2.5 x 10^-18 J The average distance an electron travels between collisions is 2.0 micrometers. What acceleration must an electron have to gain 2.5 x 10^-18 J of kinetic energy in this distance? What force must act on an electron to give it the acceleration found in Part A? What strength electric field will exert this much force on an electron? This is the breakdown field strength. (Note: The measured breakdown field strength is a little less than your calculated value because our model of the process is a bit too simple. Even so, your calculated value is close.) Suppose a free electron in air is 1.3 cm away from a point charge. What minimum charge must this point charge have to cause a breakdown of the air and create a spark?

Explanation / Answer

PART A- KE= 1/2*m*V^2

so if KE=2.5*10^-18 J

1/2*m*v^2= 2.5*10^-18

so V^2= 2KE/m

and mass of electron =9.1*10^-31 Kg

v^2=5.4945*10^12

so v^2=u^2+2as

or 5.4945*10^12=0+2a*2*10^-6

so a= 1.37*10^18 m/s^2

B). Force= ma

= 9.1*10^-31*1.37*10^18

= 1.25*10^-12 N

C).qE= F

so E= F/q

q= 1.6*10^-19

so

E=7.8125*10^6 N/C

D).for this KQ/R^2=7.8125*10^6

so 0*10^9*q/0.103^2=7.8125*10^6

so Q= 1.567*10^-7 C

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