Please show work and label each seperate answer. thanks. You\'ve made the finals

Question

Please show work and label each seperate answer. thanks.

You've made the finals of the Science Olympics! As one of your tasks, you're given 1.4[g] of copper and are asked to make a cylindrical wire, using all the metal, with a resistance of 1.5[Ohm]. Assume that copper has a mass density of rho m and a resistivity of rho. What are the length and area of the wire that you create? Consider two wires of different lengths made of copper. They will have the same resistance if and only if. . . what? Express your conclusion mathematically.

Explanation / Answer

R=rho*length/area

here volume = length*area of cross section

volume= mass/ (density mass)

now length = volume * area

length= mass*area/density mass

R= rho*mass*area/(density mass*area)

R= rho*mass/density mass

same resistance

then L1*rho1/area1 = L2*rho2/area2

rho is same

so L1/Area1 = L2/Area2

for same resisitvity

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