Problem 19.101 The figure shows an electron entering a parallel-plate capacitor

Question

Problem 19.101 The figure shows an electron entering a parallel-plate capacitor with a speed of 5.9 Problem 19.101 The figure shows an electron entering a parallel-plate capacitor with a speed of 5.9 Problem 19.101 The figure shows an electron entering a parallel-plate capacitor with a speed of 5.9 The figure shows an electron entering a parallel-plate capacitor with a speed of 5.9 The figure shows an electron entering a parallel-plate capacitor with a speed of 5.9 Problem 19.101 The figure shows an electron entering a parallel-plate capacitor with a speed of 5.9

Explanation / Answer

time taken to cross the plates, t = d/v = 0.025/5.9*10^6 = 4.237*10^-9 s

deflection in y direction,
y = 0.5*a*t^2

a = 2*y/t^2

= 2*0.00618/(4.237*10^-9)^2

= 6.89*10^14 m/s^2

we know, Fe = q*E

m*a = q*E

E = m*a/q

= 9.1*10^-31*6.89*10^14/1.6*10^-19

= 3918.7 N/c

B) vx = 5.9*10^6 m/s

vy = a*t = 6.89*10^14*4.237*10^-9 = 2.919*10^6 m/s

v = sqrt(vx^2+vy^2) = 6.583*10^6 m/s

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