Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Physics (1201/1202/2110/2112/2113) Gradebook ORION Downloadable eTextbook t>Open

ID: 2304395 • Letter: P

Question

Physics (1201/1202/2110/2112/2113) Gradebook ORION Downloadable eTextbook t>Open Assignment Question 1 At t-0, a flywheel has an angular velocity of 8.9 rad/s, an angular acceleration of -0.18 rad/s, and a reference line at 8o-0. (a) Through what maximum angle 0max will the reference line turn in the positive direction? What are the (b) first and (c) the reference line will be at e-emad67 At what (d) negative time and (e) positive time will the reference line be at ?--13 rad? times (a) Number (b) Number (e) Number (d) Number (e) Number Units Units Units Question Attempts: 0 of 12 used SAVE FOR LATER SUBMIT ANSWER John Wiley & Sons, Inc. All Rights A Division of John Wiley &

Explanation / Answer

here,

w0 = 8.9 rad/s

angular accelration , alpha = - 0.18 rad/s^2

let the time taken to reverse the direction be t

w = w0 alpha * t

0 = 8.9 - 0.18 * t

t = 49.4 s

a)

the maximum angle , thetam = w0 * t - 0.5 * alpha * t^2

thetam = 8.9 * 49.4 - 0.5 * 0.18 * 49.4^2 rad = 220 rad

b)

theta = thetam /6 = 36.7 rad

let the time taken be t

theta = w0 * t + 0.5 * alpha * t^2

36.7 = 8.9 * t - 0.5 * 0.18 * t^2

solving for t

t = 4.31 s or 94.6 s

the first time is 4.31 s

c)

the seccond time is 94.6 s

d)

theta = - 13 rad

let the time taken be t

theta = w0 * t + 0.5 * alpha * t^2

- 13 = 8.9 * t - 0.5 * 0.18 * t^2

solving for t

t = - 1.44 s or 100.3 s

the negative time is - 1.44 s

e)

the positive time is 100.3 s