Part A - The x Component of the Center of Gravity of All the Components Determin
ID: 2305409 • Letter: P
Question
Part A - The x Component of the Center of Gravity of All the Components Determine the component of the center of gravity of all the components. Express your answer to three significant figures and include the appropriate units. ? View Available Hintis) Learning Goal: To determine the center of gravity of a composite body using the principle of superposition. The layout shown is a representation of a machine shop Components 1 and 2 have masses of mi = 285kg and mg = 200kg, respectively. Component 3 must be treated as a distributed load, which is t = 155 kg/m . determined by the area of contact between the component and the shop floor. The dimensions shown have been measured to be a = 0.650 m, b = 2.40 m. c = 1.90 m. d = 0.650 m, e = 3.50 m, and f = 1.20 m. These dimensions represent the i and y components of the locations of the centers of gravity for the respective components. Component 3 has y cross-sectional dimensions of as - 1.00 m and ya = 0.250 m. Assume the components experience uniform weight distribution in all principle directions. The dimensions a through f locate the centroid of the respective component from the y- z plane and r - 2 plane. CH ÅT = 0? Value Units = Submit (Figure 1) Part B - The y Component of the Center of Gravity of All the Components Figure Determine the y component of the center of gravity of all the components. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) DH RÅ6 Os ? i = Value Units Submit Part C. The z Component of the Center of Gravity of All the ComponentsExplanation / Answer
m1 = 285 kg
x1, y1 = 0.650, 1.20
m2 = 200 kg
x2, y2 = ((a+b), d+e) = (3.05, 4.15)
m3 = (1 x 0.250 m^2)(155 kg/m^2) = 38.75 kg
x3, y3 = (a+b+c , d) = (4.95, 0.650)
(A) x_cm= (m1 x1 + m2 x2 + m3 x3)/(m1 + m2+ m3)
= [ (285 x 0.650) + (200 x 3.05) + (38.75 x 4.95)]/(285 + 200 + 38.75)
= 2 m
(B)
y_cm= (m1 y1 + m2 y2 + m3 y3)/(m1 + m2+ m3)
= 2.29 m