Part A - Enter an expression for the final, equilibrium temperature of the mixtu

Question

Part A - Enter an expression for the final, equilibrium temperature of the mixture, in terms of defined quantities?

PLEASE, need help ASAP

(10%) Problem 10: You mix ml 0.55 kg of ice at T 21 with m 3.2 kg of water at Tw 76 in an insulated container. OC The specific heats of ice and water are cl 2.10x103 JWOkg.oC) and c 4.19x105 JOkg. C), respectively, and the latent heat of fusion for water is Lf 3.34 x 103 J/kg 50% Part (a) Enter an expression for the final, equilibrium temperature of the mixture, in terms of the defined quantities. Grade Summary 0% Deductions Potential 100% HOME Submissions Attempts remaining: 2 4 5 6 (0% per attempt 1 2 3 detailed view mw 0% vo BACKSPACE 0% 0% Submit Feedback I give

Explanation / Answer

here,

m1 = 0.55 kg

T1 = -21 degree C

mw = 3.2 kg

Tw = 76 degree C

let the final equilibrium temprature be Tf

the heat lost by water = heat gained by ice

mw * Cw * ( Tw - Tf) = mi * ( Ci * ( 0 - (-21)) + Lf + Cw * ( Tf - 0))

3.2 * 4186 * ( 76 - Tf) = 0.55 * ( 2100 * 21 + 334000 + 4186 * Tf)

solving for Tf

Tf = 51.6 degree C

the final temprature is 51.6 degree C

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