An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform

Question

An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge denisity ?1 = 0.54 ?C/m2. Another infinite sheet of charge with uniform charge density ?2 = -0.46 ?C/m2 is located at x = c = 25 cm.. An uncharged infinite conducting slab is placed halfway in between these sheets ( i.e., between x = 10.5 cm and x = 14.5 cm).

Potential of Infinite Sheets of Charge and Conducting Slab An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge density 1 = 0.54 C/m. Another infinite sheet of charge with uniform charge density 2 =-0.46 C/m" is located at x-c-25 cm.. An uncharged infinite conducting slab is placed halfway in between these sheets ( i.e., between x = 10.5 cm and x = 14.5 cm). a/2 1) What is Ex(P), the x-component of the electric field at point P, located at (x,y) = (5.25 cm, o)? N/C Submit 2) what is a, the charge density on the surface of the conducting slab at x = 10.5 cm? /mz Submit 3) What is V(R) - V(P), the potentital difference between point P and point R, located at (x,y) = (5.25 cm,-14.5 cm)? Submit 4) What is V(S) - V(P), the potential difference between point P and point S, located at (x,y)- (19.75 cm, -14.5 cm)? Submit 5) what is Ex(T), the x-component of the electric field at point T, located at (x,y) = (30.25 cm, -14.5 cm)? N/C Submit

Explanation / Answer

1) Ex(P) = (sigma1 + sigma2)/(2*epsilon)

= (0.54 + 0.46)*10^-6/(2*8.854*10^-12)

= 56471.7 N/c

2) sigma_a = -(0.54 + 0.46)*10^-6/2

= -0.5*10^-6 C/m^2

= -0.5 micro C/m^2

3) VR - VP = 0

4) VS - Vp = -E*d

= -56471.7*(0.1975 - 0.0525 - 0.04)

= -5929.5 volts

5) Ex(T) = (sigma1 - sigma2)/(2*epsilon)

= (0.54 - 0.46)*10^-6/(2*8.854*10^-12)

= 4517.7 N/c

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---