Can anyone tell me what I\'m doing wrong? I don\'t understand how my evaluated i

Question

Can anyone tell me what I'm doing wrong? I don't understand how my evaluated integral is wrong but I got the answer right.

(1 point) (1 point)Get help ente Get help entering answersSee a similar example (.PDF) Get help ente Recall that lim dr 3 4r5 because the integral on the left is improper irstevaluate. J3 Step 1. First evaluate: da 4.r5 Answer = -(1/(4T4) Note: Your answer should be a function of t Step 2. Now find the limit as t oo of your answer in Step 1 Answer 1/1 296 Leave your answer as a number, or as INF or -INF (for +oo or-o, respectively)

Explanation / Answer

[3 to ] 1/(4x5) dx = lim[t -> ] [3 to t] 1/(4x5) dx

==> lim[t -> ] [3 to t] (1/4) x-5 dx

==> lim[t -> ][3 to t] (1/4) x-5+1/(-5 +1)     since xn dx = xn+1/(n +1) ; here n = -5

==> lim[t -> ][3 to t] (-1/16) x-4

==> lim[t -> ] (-1/16) (t-4 - 3-4)

==> lim[t -> ] (-1/16) ( 1/t4 - 1/34)

==> lim[t -> ] (-1/16) [(81 - t4)/(81t4) ]

==> lim[t -> ] [(t4 - 81)/(1296t4) ]

Hence [3 to t] 1/(4x5) dx = (t4 - 81)/(1296t4)

lim[t -> ] [3 to t] 1/(4x5) dx = lim[t -> ](t4 - 81)/(1296t4)

==> lim[t -> ]t4 (1 - 81/t4)/(1296t4)

==> lim[t -> ](1 - 81/t4)/1296

==> (1 - 0)/1296

==> 1/1296

Hence [3 to ] 1/(4x5) dx = 1/1296

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