Please show work, thank you! :) in past el te voter turnout was 75% n a survey,
ID: 2928084 • Letter: P
Question
Please show work, thank you! :)
in past el te voter turnout was 75% n a survey, 923 sub ects were asked they voted in the ele on a Find the mean a d standard deviation or the n ten of voters go s of said that they voted in the election s this result consistent with the turnout, or is this result unlikely to o cur with a turnout of 75%? why or why not c Based on these re does it appear t at a cu obtained by asking voters how they acted? te s ey f 923 o to o ng res s can be st a. " | | (Round to one decimal place as needed.) [] (Round to one decimal place as needed.) b. Is the result of 726 voting in the election usual or unusual? A. This result is unusual because 726 is within the range of usual values O B. This result is usual because 726 is within the range of usual values. C. This result is unusual because 726 is greater than the maximum usual value. D. This result is unusual because 726 is below the minimum usai value c. Does it appear that accurate voting results can be obtained by asking voters how they acted? O A. No, because it appears that substantilly more people say that they voted than the proportion of people who actually did vote Yes, because the results indicate that 75% is a possible turnout. No, because it appears that substantially fewer people say that they voted than the proportion of people who actually did vote. B. O c Click to select your answer(s).Explanation / Answer
a) mean =np =923*0.75 =692.25
std deviation =(np(1-p))1/2 =(923*0.75*0.25)1/2 =13.1553
b)as range of usual values are 2 std deviation from mean.
here mamximum usual value =mean +2*Std deviation =718.56
option C is correct. the result is unusual becasue 726 is greater....
c)option A is correct