In the circuit given below the capacitor is pre charged at a voltage The switch
ID: 2990536 • Letter: I
Question
In the circuit given below the capacitor is pre charged at a voltage The switch that is initially open is closed at t=0. Also L=C in terms of numerical values. Please find R (positive value) so the circuit is critically damped. R = 0 Ohm R = 1 Ohm R = 2 Ohm R = 3 Ohm R = 4 Ohm R = 5 Ohm For the same circuit, please find the initial values i(0+) and i'(0) i(0+) = 0, i'(0+)=0 i(0+) = Vo/R, i'(0+)=0 i(0+) = -Vo/R, i'(0+)= Vo/L i(0+) = 0, i'(0+)=Vo/L None of the above For the same circuit as above, please find the capacitor voltage Vc(t) for t>0 Vc(t) = Vo*exp(-0.5*R/L*t) Vc(t) = Vo*(l+0.5*R/L*trexp(-0.S*R/L*t) Vc(t) = Vo*(l+R/L*t)*exp(-0.5*R/L*t) Vc(t) = Vo*(l-0.5*R/L*t)'exp(-0.5*R/L*t) None of the aboveExplanation / Answer
1.
R=2ohms
2.
i(0+)=0
i'(0+)=V0/L
3.
VC(t)=V0*(1+0.5*R/L*t)*exp(-0.5*R/L*t)