Consider the following system. 2 springs with stiffnesses k 1 and k 2 are arrang

Question

Consider the following system. 2 springs with stiffnesses k1and k2 are arranged as shown. The rigid bar remains horizontal when the force F is zero. Determine the equivalent spring constant keqof the system that relates the force applied to the displacement x (such that F=keqx).

-Since the springs are different and the force is off-centered, the bar will NOT remain horizontal when the force F is applied.

-Ignore the elasticity of the bar itself.

Consider the following system. 2 springs with stiffnesses k1 and k2 are arranged as shown. The rigid bar remains horizontal when the force F is zero. Determine the equivalent spring constant keq of the system that relates the force applied to the displacement x (such that F=keqx). -Since the springs are different and the force is off-centered, the bar will NOT remain horizontal when the force F is applied. -Ignore the elasticity of the bar itself.

Explanation / Answer

Since the springs are connected in parallel to the bar, The net Keq will be sum of the k of the 2 springs

so Keq = K1 + k2

and Force F = Keqx

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---